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Write the following equation in ionic form. MnO_(2)+4HCl to MnCl_(2)+2H_(2)O+Cl_(2) |
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Answer» Solution :In this REACTION HCl and `MnCl_(2)` are ionic in NATURE. Writing these comounds in ionic from, `MnO_(2)+4H^(+)+4Cl^(-)=MN^(2+)+2Cl^(-)+2H_(2)O+Cl_(2)` `2Cl^(-)` ION are common on both sides, so these are cancelled. The desired ionic equation reduceds, to , `MnO_(2)+4H^(+)+2Cl^(-)=Mn^(2+)+2H_(2)O+Cl_(2)` |
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