1.

Write the formula for finding the sum of n terms of a G.P.

Answer»

Let ‘a’ be the first term and ’r’(≠) be the common ratio of the given G.P.The general teams of G.P. If Sn denotes the sum of ‘n’ terms, then,

Sn = a((1 - rn)/(1 - r)) r ≠ 1

This can also written as

Sn = a((rn - 1)/(r - 1))

Note: (1) Sn = a + ar + ar+….. +arn-1 

(2) If r = 1, then Sn = a + a + a +……………+a – na 

(3) If r = 1, then formulas for Sn fail 

(4) If r < 1, then use  Sn = a((1 - rn)/(1 - r))

(5) If r > 1, use  Sn = a((rn - 1)/(r - 1))

(6) Sum of an infinite G.P.,a + ar + ar2  + ..... is a/(1 - r), - 1 r < 1

(7) If a, b, c are in G.P.then ‘b’ is the G.M. (geometric mean) between a and c, then b2  = ac ⇒ b = √ac

(8) If A and G are A.M. and G.M. of two given distinct positive real numbers, then relation between A and G is A > G.

Sum of G.P. up to n terms if 1st term is a and

the common ratio is r.

Sn =a.(1-rn)/(1-r)………….(1) while r < 1 .

or

Sn =a.(rn-1)/(r - 1)………(2) while r > 1 .

Sum up to infinite terms = a/(1-r).



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