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Write the formula for finding the sum of n terms of a G.P. |
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Answer» Let ‘a’ be the first term and ’r’(≠) be the common ratio of the given G.P.The general teams of G.P. If Sn denotes the sum of ‘n’ terms, then, Sn = a((1 - rn)/(1 - r)) r ≠ 1 This can also written as Sn = a((rn - 1)/(r - 1)) Note: (1) Sn = a + ar + ar2 +….. +arn-1 (2) If r = 1, then Sn = a + a + a +……………+a – na (3) If r = 1, then formulas for Sn fail (4) If r < 1, then use Sn = a((1 - rn)/(1 - r)) (5) If r > 1, use Sn = a((rn - 1)/(r - 1)) (6) Sum of an infinite G.P.,a + ar + ar2 + ..... is a/(1 - r), - 1 r < 1 (7) If a, b, c are in G.P.then ‘b’ is the G.M. (geometric mean) between a and c, then b2 = ac ⇒ b = √ac (8) If A and G are A.M. and G.M. of two given distinct positive real numbers, then relation between A and G is A > G. Sum of G.P. up to n terms if 1st term is a and the common ratio is r. Sn =a.(1-rn)/(1-r)………….(1) while r < 1 . or Sn =a.(rn-1)/(r - 1)………(2) while r > 1 . Sum up to infinite terms = a/(1-r). |
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