Write the intercept cut-off by plane 2x + y - z = 5 on X-axis.

1.	Write the intercept cut-off by plane 2x + y - z = 5 on X-axis.
Answer» Given equation of plane is 2x + y - z = 5. On dividing both sides by 5, we get 2x/5 + y/5 - z/5 = 1 on comparing above equation of plane with the intercept form of equation of plane. x/a + y/b + z/c = 1 where, a = x-intercept, b = y-intercept and c = z-intercept. we get, a = 5/2 i.e., intercept cut off on X-axis = 5/2.

Answer»

Given equation of plane is 2x + y - z = 5.

On dividing both sides by 5, we get

2x/5 + y/5 - z/5 = 1

on comparing above equation of plane with the intercept form of equation of plane.

x/a + y/b + z/c = 1

where, a = x-intercept, b = y-intercept and c = z-intercept.

we get, a = 5/2

i.e., intercept cut off on X-axis = 5/2.

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