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Write the ions present in(i) Al2(CO3)3 (ii) AlBrz3 |
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Answer» Answer: Explanation: Thus, 234 grams exist in 1 Mole of Aluminum CARBONATE. ... Solution : Here ions are :- Al 3+. CO3 2-. Formula unit MASS = 27×2 + ( 12 + 48 )3. |
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