InterviewSolution
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InterviewSolution
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Write the molecular orbital electron distribution of oxygen `(O_(2))` Specify its bond order and magnetic property Fill in the blanks When `N_(2) ` goes to `N_(2)^(o+)`, the `N-N` bond distance___ and when `O_(2)` goes to `O_(2)^(o+)` the `O-O` bond distance ____ . |
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Answer» `O_(2):KK^(**) (sigma2s)^(2) (sigma^(**) 2p_(z))^(2) (pi 2p_(x))^(2) (pi 2p_(y))^(2)` `(pi^(**)2p_(x))^(1) (pi ^(**) 2p_(y))^(1)` Bond order ` =(1)/(2) (8-4)` The molecule is paramagnetic due to two unpaired electrons in `(pi^(**) 2p_(x))^(1) (pi ^(**)2p_(y))^(1)` (b) Increases, decreases . |
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