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Write the molecular orbital electronic configuration for carbon monoxide molecule. Calculate its bond order and comment on its magnetic property. |
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Answer» SOLUTION :`sigma1s^(2) sigma^(**) 1s^(2) sigma 2s^(2) sigma^(**) 2 s^(2) pi 2 px^(2)=pi 2 py^(2)` bond ORDER `=(N_(B)-N_(A))/2=1/2(8-4)=2` Since there are no UNPAIRED electron it is diamagnetic in nature. |
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