1.

Write the Nernst equation and Cell reaction of the following cell Zn|Zn^(2+)(0.01)M)||Cu^(2+)(0.01)M)|Cu

Answer»

Solution :`ZntoZn^(2+)+2E`
`Cu^(2+)+2etoCu`
`Zn+Cu^(2+)TOZN^(2+)+Cu` ( CELL reaction )
NERNST equation for the above cell reaction is
`E_("cell")=E_("cell")^(@)+(0.0591)/(2)LOG""([Cu^(2+)])/([Zn^(2+)])`
`E_("cell")=E_("cell")^(@)+(0.591)/(2)log""(0.01)/(0.01)`
`E_("cell")=E_("cell")^(@)+zero`
`E_("cell")=E_("cell")^(@)`


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