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Write the Nernst equation and compute the emf of the following cell at 298 K: Sn(s)|Sn^(2+)(0.05M)||H^+(0.02M)|H_2,1atm//Pt

Answer»

Solution :Nernst EQUATION:
`SN+2H^(+) to Sn^(2+)+H_2`
conc. of `Sn^(2+)=0.05M`
`H^+=0.02M`
`H_2=1 pressure//atm`
`E_(Sn^(2+)//Sn)^@=-0.136V`
`E_(cell)^@=E_(cell)^@-0.059/2log""(Pro d UCTS)/(Reactants)`
`E_(cell)=E_(cathode)^@-E_(ANODE)^@`
`=0-(-1.36V)`
=1.36V
`E_(cell)=1.36-0.059/2log""((0.05)(1))/(0.02)^2`
`=1.36 -0.0295 times log 0.05`
`=1.36 -0.0295 times log""(0.05 times 10^2)/(0.02 times 0.02)`
`=1.36 -0.0295 times 2.09`
`=1.36 -0.06`
=1.3V


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