1.

Write the Nernst equation for the E_(cell) reaction in the Daniell cell. How will the E_(cell) be affected when concentration of Zn^(2+) ions is increased ?

Answer»

Solution :* Nernst equation for DANIELL cell is as follows:
`E_(cell)=E_(cell)^(@)-(0.0591)/(2)log_(10)[(ZN^(2+))/(Cu^(2+))]`
* If concentration of `Zn^(2+)` ions increases, `E_(cell)` value GET DECREASES.
* On increase in concentration of `Zn^(2+)` it increases the value of,
`[(Zn^(2+))/(Cu^(2+))]` so `log[(Zn^(2+))/(Cu^(2+))]` value increases.
* So, subtractive value of `E_(cell)^(Theta)` ALSO increases, hence, `E_(cell)` get decreases.


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