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Write the nth term of the series \(\frac{3}{7.11^2}\) + \(\frac{5}{8.12^2}\) + \(\frac{7}{9.13^2}\) + ..... |
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Answer» N term of 3, 5, 7,… is 2n + 1 nth term of 7, 8, 9,… is 6 + n nth term of 112 , 122 , 132, … is (10 + n)2 ∴ nth term of the given series = \(\frac{2n\,+\,1}{(6+n)(10+n)^2}\) |
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