InterviewSolution
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InterviewSolution
| 1. |
Write the number of ways in which 5 boys and 3 girls can be seated in a row so that each girl is between 2 boys. |
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Answer» 5 boys can be seated in 5! ways to sit in a row. Now, we can place 3 girls in 4 empty seats between them so that each girl is between 2 boys, and this can be done in 4P3 = 24 ways. As, the operations are dependent, so, the number of ways in which 5 boys and 3 girls can be seated in a row so that each girl is between 2 boys. = 5! \(\times\)24 = 2880. The discussion can be shown pictorially as :
[X = 4 empty seats between 2 boys(B)] |
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