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Write the overall rendox reaction which takes place in the galvanic cell, Pt(s)abs(Fe^(2+)(aq), Fe^(3+)(aq))abs(MnO_(4)^(-)(aq), H^(+)(aq),Mn^(2+)(aq))Pt(s) |
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Answer» Solution :Oxidation at anode `Fe^(2+) rarr Fe^(3+)+e^(-) "...(1)"` REDUCTION at cathode `MnO_(4)^(-)+8H^(+)+5e^(-) rarr Mn^(2+)+4H_(2)O"...(2)"` To balance multiply equation `(1) TIMES 5` and equation `(2) times 1` `5Fe^(2+)+MnO_(4)^(-)+8H^(+) rarr Mn^(2+)4H_(2)O+5Fe^(3+)` Overall REDOX reaction is `5Fe^(2+)""_((aq))+MnO_(4(aq))^(-)+8H_((aq))^(+) rarr 5Fe^(3+)""_((aq))+Mn^(2+)""_((aq))+4H_(2)O(l)` |
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