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Write the position isomers of (a) C_(3)H_(6)Cl_(2) (b) C_(3) H_(5) Cl |
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Answer» Solution :The number of POSITION isomers for the formula `C_(3)H_(6)CI_(2)`. Is four. `(1)underset(1,1-"Dichloropropane")(CH_(3)-CH_(2)-CHCI_(2))` `(2) underset(2,2-"Dichlorophane")(CH_(3)-C CI_(2)-CH_(3))` (3) `underset(1,2-"Dichloroprophane")(CH_(3)-CHCI-CH_(2)CI)` (4) `underset(1,3-"Dichloropropane")(CH_(2)CI-CH_(2)CI)` (B) The number of position isomers for the formula `C_(3)H_(5)CI` is three. (1) `underset(3-"Chlorpropane")(CH_(2)=CH-CH_(2)CI)` (2) `underset(2-"Chloropropane")(CH_(2)=C CI-CH_(3))` (3) `underset(1-"Chloropropane")(CHCI=CH-CH_(3))` |
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