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Write the principal value of\(sin^{-1}\{cos(sin^{-1}\frac{1}{2})\}\). |
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Answer» Given \(sin^{-1}\{cos(sin^{-1}\frac{1}{2})\}\) =\(sin^{-1}\{cos(sin^{-1}(sin\frac{\pi}{3}))\}\) = \(sin^{-1}\{cos(\frac{\pi}{3})\}\) = sin-1 (1/2) \(=sin^{-1}(sin\frac{\pi}{3})\) = \(\frac{\pi}{3}\) |
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