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Write the products of the following reaction : 6XeF_(4)+12H_(2)O to Is this reaction a disproportionation reaction ? Give reasons in support of your answer. |
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Answer» Solution :`6XeF_(4)+12H_(2)O to 4Xe+2XeO_(3)+24HF+3O_(2)` This is a DISPROPROTIONATION reaction. Oxidation number of Xe in `XeF_(4)=4` Oxidation number of Xe as element = 0 Oxidation number of Xe in `XeO_(3)=6` Thus it decomposes into TWO COMPOUNDS where one compound has GREATER oxidation number and the second compound has smaller oxidation number than the original. |
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