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| 1. |
Write the reaction products of 2-pentene when oxidised with acidified potassium permanganate at 100^(@)C. |
| Answer» Solution :`underset("2-Pentene")(CH_(3)-CH_(2))-CH=CH-CH_(3)+4(O)underset("Acid")overset(KMnO_(6))tounderset("Propanoic acid")(CH_(3)CH_(2)COOH)+underset("Ethanoic acid")(CH_(3)COOH)` | |