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Write the relationship between equilibrium constant and enthapy. |
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Answer» Solution :The value of equilibrium constant changes with CHANGE in TEMPERATURE. If `K_(1)` and `K_(2)` are equilibrium constants at temperature `T_(1)` and `T_(2)`. `DeltaH` - Heat of reaction at constant pressure. Then, `"log"(K_(2))/(K_(1))=(DeltaH)/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]` |
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