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Write the resonance structure for SO_(3), NO_(2) and NO_(3)^(-) . |
Answer» Solution :Resonance structure of `SO_(3)` : Structure (IV) is hybrid. Total valence electron = 24In `SO_(3)` total electron= 8 bonding + 16 nonbonding = 24  NITROGEN dioxide `(NO)_(2)` molecule : (I) (II) resonance structure and (III) is hybrid structure. Total valence electron= Two O (12) + N of (5) = 17 Total electron in `NO_(2)` = 6 bonding + 11 non-bonding = 17 Nitrate Ion `(NO_(3)^(-)) `:  Total valence electron= N (5) +`O_(3)`(18) + 1 = 24 Total electron in `NO_(3)^(-)` = 8 FOUR BOND + 16 non-bonding= 24 |
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