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Write the smallest digit and the greatest digit in the blank space of each of the following number so that the number formed is divisible by 3:(a) ___6724(b) 4765___2 |
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Answer» (a) __ 6724:- Sum of the remaining digits = 6 + 7 + 2 + 4 = 19 To make the number divisible by 3, the sum of its digits should be divisible by 3. The smallest multiple of 3 Which comes after 19 is 21. ∴ Smallest number = 21 – 19 = 2 Now 2 + 3 + 3 = 8 However 2 + 3 + 3 + 3 = 11 If we put 8, then the sum of the digits will be 27 and as 27 is divisible by 3 the number will also be divisible by 3. Therefore the largest number is 8. (b) 4765 ___ 2:- Sum of the remaining digits = 24 To make the number divisible by 3, the sum of its digits should be divisible by 3. As 24 is already divisible by 3, the smallest number that can be place here is 0 Now, 0 + 3 = 3 3 + 3 = 6 3 + 3 + 3 = 9 However, 3 + 3 + 3 + 3 = 12 If we put 9 then the sum of the digits will be 33 and as 33 is divisible by 3, the number will also be divisible by 3. Therefore, the largest number is 9. |
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