Write the state of hybridization of all the atoms in CH_(2)=C=CH_(2) and draw its orbital structure. Do the two atoms on C_(1) lie in the same plane in which hydrogens on C_(3) lie. Explain.

Write the state of hybridization of all the atoms in CH_(2)=C=CH_(2) a

1.	Write the state of hybridization of all the atoms in CH_(2)=C=CH_(2) and draw its orbital structure. Do the two atoms on C_(1) lie in the same plane in which hydrogens on C_(3) lie. Explain.
Answer» Solution :The gross structure of allene `(C_(3)H_(4))` is `OVERSET(1)(C)H_(2)=overset(2)(C)=overset(3)(C)H_(2)` The carbon atoms 1 and 3 are `sp^(2)`-hybridized SINCE each one of them is joined by a double bond. In CONTRAST, carbon atom 2 is sp-hybridized since it has two double bonds. Thus, the two `pi`-bonds in allene like in acetylene are perpendicular to each other as shown below. whereas `H_(c)` and `H_(d)` lie in the plane of the paper while `H_(a)` and `H_(B)` lie in a plane perpendicular to the plane of the paper. Thus, the molecule as a WHOLE is non-planar.