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Write the total number of possible outcomes in a throw of 3 dice in which at least one of the dice shows an even number. |
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Answer» Total possible outcomes in a throw of 3 dice = 63 = 216. When, No die shows an even number i.e. all the die shows odd number (1, 3 or 5), Then, The number of possible outcomes = 33 = 27. Hence, The total number of possible outcomes in a throw of 3 dice in which at least one of the dice shows an even number = 216 - 27 = 189. |
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