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Write the truth table for the circuit shown in Fig. Name the gate of which this circuit is performing. |
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Answer» Here, `y_(1)=bar(A.B)=barA+barB` `y_(2)=A+B` `y=y_(1).y_(2)` `=(bar(A.B)).(A+B)` `=(barA+barB).(A+B)` `=bar.(A+B)+bar.(A+B)` `=bar.A+bar.B+bar.A+bar.B` `0+bar.B+bar.A+0` `=A.bar+B.bar` It is a Boolean expression of XOR gate. Thus XOR gate is produced. Truth table of this gate is given below. `|{:(A,B,y_(1)=bar(A.B),y_(2)=A+B,y=(bar(A.B)).(A+B)),(0,0,1,0,0),(0,1,1,1,1),(1,0,1,1,1),(1,1,0,1,0):}|` |
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