1.

Write the value of (1–sin2θ)sec2θ

Answer»

(1– sin2θ) sec2θ = cos2θ. sec2θ  (∵ sin2θ + cos2θ = 1)

=\(\cfrac{1}{sec^2 \theta}\). sec2θ = 1. (\(\because\) cosθ = \(\cfrac{1}{sec \theta}\))

Hence, the value of (1– sin2θ) sec2θ is 1.



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