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Write the value of (1–sin2θ)sec2θ |
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Answer» (1– sin2θ) sec2θ = cos2θ. sec2θ (∵ sin2θ + cos2θ = 1) =\(\cfrac{1}{sec^2 \theta}\). sec2θ = 1. (\(\because\) cosθ = \(\cfrac{1}{sec \theta}\)) Hence, the value of (1– sin2θ) sec2θ is 1. |
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