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Write the value of sin–1(1550°). |
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Answer» Given sin-1 (sin 1550°) = sin-1 (sin (1440° + 110°)) = sin-1 (sin (360° × 4 + 110°)) We know that sin (2nπ + θ) = sin θ = sin-1 (sin 110°) We know that sin-1 (sin θ) = π – θ, if θ ∈ [π/2, 3π/2] = 180° - 110° = 70° ∴ sin-1 (sin 1550°) = 70° |
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