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Write the value of sin–1 (sin(–600°)). |
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Answer» Given sin-1 (sin (-600°)) = sin -1 (sin (-600 + 360 × 2)) We know that sin (2nπ + θ) = sin θ = sin (sin 120°) We know that sin-1 (sin θ) = π – θ, if θ ∈ [π/2, 3π/2] = 180° - 120° = 60° ∴ sin -1 (sin (-600°)) = 60° |
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