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Write the value of `sin^(2)theta cos^(2)theta(1+tan^(2)theta)(1+cot^(2)theta).` |
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Answer» Correct Answer - 1 Given expression `=sin^(2)theta(1+cot^(2)theta)cos^(2)theta(1+tan^(2)theta)` `=(sin^(2)theta "cosec"^(2)theta)(cos^(2)thetasec^(2)theta)=(1xx1)=1.` |
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