Write the value of tan-1[2sin(2cos-1(√3/2))] – InterviewSolution

1.

Write the value of tan-1[2sin(2cos-1(√3/2))]

Answer»

tan^-1[2sin(2cos^-1(√3/2))]

= tan^-1[2sin(2(π/6))] = tan^-1[2sin(π/3)] = tan^-1[2 x √3/2]

= tan^-1√3 = π/3

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