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Write the value of tan-1{tan (\(\frac{15\pi}4\))}. |
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Answer» Given tan-1 {tan (15π/4)} = tan-1 {tan (4π - π/4)} We know that tan (2π – θ) = -tan θ = tan-1 (-tan π/4) = tan-1 (-1) = -π/4 ∴ tan-1 {tan (15π/4)} = -π/4 |
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