Saved Bookmarks
| 1. |
Write the value of\(tan(2tan^{-1}\frac{1}{5})\). |
|
Answer» Let tan θ = 1/5 Given tan (2 tan-1 1/5) = tan 2θ We know that \(tan2\theta=\frac{2tan\theta}{1-tan^2\theta}\) \(=\frac{2\times\frac{1}{5}}{1-\frac{1}{25}}\) \(=\frac{\frac{2}{5}}{\frac{24}{25}}\) \(=\therefore tan(2tan^{-1}\frac{1}{5})=\frac{5}{12}\) |
|