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Write the value of the expression \(tan(\frac{sin^{-1}x+cos^{-1}x}{2})\), when x= \(\frac{\sqrt{3}}{2}\) |
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Answer» Given \(tan(\frac{sin^{-1}x+cos^{-1}x}{2})\) when x= \(\frac{\sqrt{3}}{2}\) ⇒ \(tan(\frac{sin^{-1}x+cos^{-1}x}{2})\)\(=tan(\frac{sin^{-1}\frac{\sqrt{3}}{2}+cos^{-1}\frac{\sqrt{3}}{2}}{2})\) We know that sin-1 x + cos-1 x = π/2 = tan (π/4) \(\therefore tan(\frac{sin^{-1}x+cos^{-1}x}{2})\)=1 |
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