1.

Write the value of the expression \(tan(\frac{sin^{-1}x+cos^{-1}x}{2})\), when x= \(\frac{\sqrt{3}}{2}\)

Answer»

Given \(tan(\frac{sin^{-1}x+cos^{-1}x}{2})\) when x= \(\frac{\sqrt{3}}{2}\)

⇒ \(tan(\frac{sin^{-1}x+cos^{-1}x}{2})\)\(=tan(\frac{sin^{-1}\frac{\sqrt{3}}{2}+cos^{-1}\frac{\sqrt{3}}{2}}{2})\)

We know that sin-1 x + cos-1 x = π/2 

= tan (π/4)

\(\therefore tan(\frac{sin^{-1}x+cos^{-1}x}{2})\)=1



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