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Write three divisions of integers such that the fractional form of each will be 24/5. |
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Answer» 1. \(\frac{24}{5} = \frac{24 \times 1}{5 \times 1} = \frac{24}{5} = 24 \div 5\) 2. \(\frac{24}{5} = \frac{24 \times 2}{5 \times 2} = \frac{48}{10} = 48 \div 10\) 3. \(\frac{24}{5} = \frac{24 \times (-10)}{5 \times (-10)} = \frac{-240}{-50} = (-240) \div (-50)\) |
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