1.

Writing Lewis Struchures for Molceules with more than One central atom. Write the Lewis structure for methanol (molecularfarmula CH _(4) O), on important industrical alcohol tht is being used as a gasoline alternative in car engines.

Answer»

Solution :Step:1 Place the atoms relative to each other. The H atoms can have only one bond, so C and O must be adjacent to each other. In nearly all their compounds, C has four BONDS and O has TWO, so we arrange the H atoms to shown this.
Step : 2 Find sum of valence electrons
`[1xx C (4e ^(-)) ] + [1xxO (6e ^(-)) ] + [ 4 xx H (1e ^(-)) ] = 14 e ^(-) {:(""H),(H " "C ""O ""H),(""H):}`
Step :3 Add single bonds and subtract `2e^(-)` for each bond. `H- underset(H) underset(|) OVERSET(H) overset(|) (C) -O-H`
Five bonds ue `10 e^(-), so 14 e ^(-)- 10 e ^(-)` leaves `4e ^(-)` remaining.
Step :4 Add remaining electrons in pairs.

Carbond already has an octet, so the four remaining VELENCE `e ^(-)` from two lone pairs on O and give the Lewis strructure for methanol.


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