Saved Bookmarks
| 1. |
Writing Lewis Struchures for Molceules with more than One central atom. Write the Lewis structure for methanol (molecularfarmula CH _(4) O), on important industrical alcohol tht is being used as a gasoline alternative in car engines. |
|
Answer» Solution :Step:1 Place the atoms relative to each other. The H atoms can have only one bond, so C and O must be adjacent to each other. In nearly all their compounds, C has four BONDS and O has TWO, so we arrange the H atoms to shown this. Step : 2 Find sum of valence electrons `[1xx C (4e ^(-)) ] + [1xxO (6e ^(-)) ] + [ 4 xx H (1e ^(-)) ] = 14 e ^(-) {:(""H),(H " "C ""O ""H),(""H):}` Step :3 Add single bonds and subtract `2e^(-)` for each bond. `H- underset(H) underset(|) OVERSET(H) overset(|) (C) -O-H` Five bonds ue `10 e^(-), so 14 e ^(-)- 10 e ^(-)` leaves `4e ^(-)` remaining. Step :4 Add remaining electrons in pairs. ![]() Carbond already has an octet, so the four remaining VELENCE `e ^(-)` from two lone pairs on O and give the Lewis strructure for methanol. |
|