x = 1+(3 ) /(1 ! )xx (1 )/(6) +( 3 xx 7 ) /(2 ! )( (1 )/(6) ) ^ 2+ (3 xx 7 xx 11 ) /(3 ! )((1 )/(6))^ 3+… rArrx ^4 =

x = 1+(3 ) /(1 ! )xx (1 )/(6) +( 3 xx 7 ) /(2 ! )( (1 )/(6) ) ^ 2+ (3

1.	x = 1+(3 ) /(1 ! )xx (1 )/(6) +( 3 xx 7 ) /(2 ! )( (1 )/(6) ) ^ 2+ (3 xx 7 xx 11 ) /(3 ! )((1 )/(6))^ 3+… rArrx ^4 =
Answer» `81 ` `54 ` `27` `8` Solution : ` x = 1+(3 ) /(1! )XX(1 )/(6)+(3 xx 7 ) /(2 ! )((1 )/(6))^ 2+(3 xx 7 xx 11 ) /(3 ! )((1 )/(6))^(3)+…` `x= (1 - y ) ^(-p//q ) ` `p =3,p + q= 7,(y ) /(q)= (1 )/(6) ` `q =4 ` ` (y) /(4)=(1 )/(6)` `rArry =(4 ) /(6)` ` thereforey=(2 ) /(3)` ` x = (1 -(2 ) /(3) ) ^(-3//4)` ` RARRX =((1)/(3)) ^( -3/4)` `rArrx=3^(3//4)` ` rArr x = 4 sqrt(27)` `thereforex ^ 4 =27 `

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x = 1+(3 ) /(1 ! )xx (1 )/(6) +( 3 xx 7 ) /(2 ! )( (1 )/(6) ) ^ 2+ (3 xx 7 xx 11 ) /(3 ! )((1 )/(6))^ 3+… rArrx ^4 =

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