((x - 100x + 10)Given the parallelogram, solve for x.O 9080100180

1.	((x - 100x + 10)Given the parallelogram, solve for x.O 9080100180
Answer» x+10+x-10=180; 2x=180; x=180/2=90 opposite angle of parallelogram is equalsum of all angle = 360two adjacent angle sum is 180x+10+ x-10= 1802x= 180x= 180/2= 90 90 is correct answer 90 is the correct Answer x+10+x+10=1802x+20=1802x=180-20x=160/2x=80 x = 90 is correct answer let ABCD be the given parallelogramin parallelogram ABCD angle A+angle D=180because sum of adjacent angles of parallelogram is supplementary =x-10+x+10=180x-x-10+10=1800-0=180=180 hence option 4)180 is correct

Answer»

x+10+x-10=180; 2x=180; x=180/2=90

opposite angle of parallelogram is equalsum of all angle = 360two adjacent angle sum is 180x+10+ x-10= 1802x= 180x= 180/2= 90

90 is correct answer

90 is the correct Answer

x+10+x+10=1802x+20=1802x=180-20x=160/2x=80

x = 90 is correct answer

let ABCD be the given parallelogramin parallelogram ABCD angle A+angle D=180because sum of adjacent angles of parallelogram is supplementary

=x-10+x+10=180x-x-10+10=1800-0=180=180

hence option 4)180 is correct

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