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`(x^(2)+1)logx` |
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Answer» `int(x^(2)+1)log x dx` `=log x. int (x^(2)+1)dx` `" "-int{(d)/(dx)logx int(x^(2)+1)dx}dx` `=logx.((x^(3))/(3)+x)-int(1)/(x)((x^(3))/(3)+x)dx+C` `=(x+(x^(3))/(3))logx-int((x^(2))/(3)+1)dx+C` `=(x+(x^(3))/(3))logx-(x+(x^(3))/(9))+C` |
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