1.

X_(2) +3Y_(2) to 2XY_(3)In this reaction 2 moles of X_(2)and 4 . 5molesof Y_(2)react to give products. Which is the limiting agent and calculate the no.of moles X_(2) , Y_(2) and XY_(3)in the reaction mixture?

Answer»

Solution :`X_(2) + 3Y_(2) to 2XY_(3)`
`{:("No.of moles",2,4.5,?),("SC",1,3,2),("RATIO",2//1,4.5//3,=),(,2(ER),1.5(LR),=):}`
` = (2)/(1) = (4.5)/(3) = (nXY_(3))/(2)`
`(4.5)/(3) = (nXY_(3))/(2) = 3 `moles
No. of moles of ` 2XY_(3) `= 3 moles


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