x−2 is a factor of f(x)=x3−ax2−bx+16. When f(x) is divided by (x−3), the remainder is −5. The value of a and b is:

x−2 is a factor of f(x)=x3−ax2−bx+16. When f(x) is divided by (x

1.	x−2 is a factor of f(x)=x3−ax2−bx+16. When f(x) is divided by (x−3), the remainder is −5. The value of a and b is:
Answer» $x - 2 is a factor of f (x) = x^{3} - a x^{2} - b x + 16. When f (x) is divided by (x - 3), the remainder is - 5. The value of a and b is:$