x = √2 then (xx)x = ………………….A) \(\frac{1}{\sqrt2}\)B)

1.	x = √2 then (xx)x = ………………….A) \(\frac{1}{\sqrt2}\)B) \(\frac{1}{4\sqrt2}\)C) \(\frac{1}{3\sqrt2}\)D) \(\frac{1}{5\sqrt2}\)
Answer» Correct option is (B) \(\frac{1}{4\sqrt{2}}\) \(x=\sqrt{2}=2^\frac12\) Then \(x^{-5}=\frac1{x^5}=\frac1{(2^\frac12)^5}\) \(=\frac1{2^\frac52}=\frac1{2^{2+\frac12}}\) \(=\frac{1}{2^2.2^\frac12}=\frac{1}{4\sqrt{2}}\) Correct option is B) \(\frac{1}{4\sqrt2}\)

x = √2 then (xx)x = ………………….A) \(\frac{1}{\sqrt2}\)B) \(\frac{1}{4\sqrt2}\)C) \(\frac{1}{3\sqrt2}\)D) \(\frac{1}{5\sqrt2}\)

Answer»

Correct option is (B) \(\frac{1}{4\sqrt{2}}\)

\(x=\sqrt{2}=2^\frac12\)

Then \(x^{-5}=\frac1{x^5}=\frac1{(2^\frac12)^5}\) \(=\frac1{2^\frac52}=\frac1{2^{2+\frac12}}\) \(=\frac{1}{2^2.2^\frac12}=\frac{1}{4\sqrt{2}}\)

Correct option is B) \(\frac{1}{4\sqrt2}\)