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(x ^ 2+x + 1 ) /((x - 1)(x -2) (x -3))=(A)/(x-1) + (B)/(x-2) + (C )/(x - 3 )rArr A + C = |
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Answer» 4 `x ^ 2+x + 1=A( x - 2 )(x - 3 ) +B( x - 1 )(x - 3 ) +C( x- 1 )(x - 2 ) ` If`x = 1` ` rArr3=A (-1)( - 2 ) ` ` A =(3 ) /(2) ` If`x=3 ` ` 3 ^ 2+ 3 + 1=0+0+ C ( 3 - 1 )(3 - 2 ) ` `rArr 13 =2C ` `rArr C =(13 ) /(2) ` A + C `= (3 ) /(2)+ (13 )/(2) ` `thereforeA + C =8 ` |
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