InterviewSolution
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InterviewSolution
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`(x^(3)-1)^((1)/(3))x^(5)` |
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Answer» `int(x^(3)-1)^(1//3)x^(5)dx" माना "x^((3)-1=t` `=int(x^(3)-1)^(1//3)x^(5)dx" माना "x^(3)-1=t` `=int(x^(3)-1)^(1//3).x^(3).x^(2)dx" "rArr 3x^(2)dx=dt` `=int t^(1//3)(t+1)(dt)/(3)" "rArr x^(2)dx=(dt)/(3)` `=(1)/(3)int t^(4//3)dt+(1)/(3)intt^(1//3)dt` `=(1)/(3).(t^(7//3))/(7//3)+(1)/(3).(t^(4//3))/(4//3)+c` `=(1)/(7)(x^(3)-1)^(7//3)+(1)/(4)(x^(3)-1)^(4//3)+c` |
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