1.

x^3+13x^2+32x+20

Answer» Let p(x) = x3 + 13x2+ 32x + 20p(-1) = (-1)3 + 13(-1)2 + 32(-1) + 20= -1 + 13 - 32 + 20 = 0∴ By Factor Theorem, x - (-1), i.e., (x + 1) is a factor of p(x).x3 + 13x2 + 32x + 20= x2(x + 1) + 12x(x + 1) + 20(x + 1)= (x + 1)(x2 + 12x + 20)= (x + 1)(x2 + 2x + 10x + 20)= (x + 1){x(x + 2) + 10(x + 2)}= (x + 1)(x + 2)(x + 10).


Discussion

No Comment Found