1.

x + 4 y = 9 \text { and } 6 x + 8 y = 15 \text { is } - a ) \frac { 3 } { 2 } \quad , b ) \frac { 3 } { 10 } c ) - \frac { 3 } { 2 } , d )

Answer»

6x+8y=153x+4y=9 so 6x+8y=18so distance=(18-15)/root(36+64) =3/root(100)=3/10



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