'X' a whole number which when divided by 23, gives the remainder 8. T

1.	'X' a whole number which when divided by 23, gives the remainder 8. Then, the remainder when (4x + 15) is divided by 23, is –1. 22. 13. 34. 4
Answer» Correct Answer - Option 2 : 1 CONCEPT: Dividend = (Quotient × Divisor) + Remainder CALCULATION: Suppose divisor is k, then, x = 23k + 8 According to the question – ⇒ (4x + 15) = [4(23k + 8) + 15] ⇒ 92k + 32 + 15 ⇒ 92k + 47 When (92k + 47) is divided by 23, then, 92k is completely divisible by 23 and leaves 1 as a remainder when 47 is divided by 23. ⇒ Rem[(92k + 47)/23] = Rem(47/23) = 1

'X' a whole number which when divided by 23, gives the remainder 8. Then, the remainder when (4x + 15) is divided by 23, is –1. 22. 13. 34. 4

Answer» Correct Answer - Option 2 : 1

CONCEPT:

Dividend = (Quotient × Divisor) + Remainder

CALCULATION:

Suppose divisor is k, then, x = 23k + 8

According to the question –

⇒ (4x + 15) = [4(23k + 8) + 15]

⇒ 92k + 32 + 15

⇒ 92k + 47

When (92k + 47) is divided by 23, then, 92k is completely divisible by 23 and leaves 1 as a remainder when 47 is divided by 23.

⇒ Rem[(92k + 47)/23] = Rem(47/23) = 1

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'X' a whole number which when divided by 23, gives the remainder 8. Then, the remainder when (4x + 15) is divided by 23, is –1. 22. 13. 34. 4

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