1.

X +AgNO_(3)rarr Y (white ppt.) Y is soluble in nitric acid an ammonia. The ppt. becomes yellowish brown upon addition of excess reagent owing to the formation of Z. If aqueous suspension of Y is boiled then it gives same product Z. Her, X and Y are:

Answer»

`CO_(3)^(2-)` and `Ag_(2)O`
`CO_(3)^(2-)` and `Ag_(2)CO_(3)`
`HCO_(3)^(-)` and `Ag_(2)CO_(3)`
`HCO_(3)^(-)` and `Ag_(2)O`

SOLUTION :`X RARR CO_(3)^(2-), Y rarr Ag_(2)CO_(3), Z rarr Ag_(2)O`


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