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X and y are disjoint sets. If n(X) = 40 and n(Y)= 28, then find n(X-y)+n(Y-X)

Answer» `n(X-Y)=n(X)-n( X cap Y)`
`n(Y-X)=n(y)-n(X cap Y)`
x and Y are disjoint sets ,ie. `n(X cap Y )=0`
`therefore n(X-Y)=n(X) and n(Y-X)=n (Y)`
`therefore n(X-Y)+n(Y-X)=n(X)+n(Y)`
= 40 + 28 = 68


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