1.

x Br_(2) + y KOH rarr KBr + KBrO_(3) + H_(2)O here the equivalent mass of Br_(2) of the reaction is how many times the equivalent mass of Br_(2) as reductant.

Answer»


Solution :Eq. WT. of `Br_(2)` in GIVEN reaction `= ( 3MW)/(5)`, Eq. wt. of `Br_(2)` as REDUCTANT `= ( MW)/( 10)`
`:. (3)/(5) ` ( M.W. ) = x TIMES `( M.W. ) /(10) :. X = 6`


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