X can do a piece of work in 10 days and Y can do the same work in 15 d

1.	X can do a piece of work in 10 days and Y can do the same work in 15 days if X and Y work for 2 days together after that X left the work then find the time taken by Y to complete the remaining work.1. 10 days2. 12 days3. 8 days4. 15 days
Answer» Correct Answer - Option 1 : 10 days Given: Time taken by X to complete the work = 10 days Time taken by Y to complete the work = 15 days They both work together for 2 days Formula used: Efficiency = Total work/Time taken Calculation: LCM of 10 and 15 = 30 = Total work Efficiency of X = 30/10 units/day ⇒ 3 units/day Efficiency of Y = 30/15 units/day ⇒ 2 units/day Total work done by X and Y together in 2 days = (3 + 2) × 2 units ⇒ 10 units Work remaining = (30 – 10) units ⇒ 20 units Time taken by Y to complete the work = 20/2 udays ⇒ 10 days ∴ Time taken by Y to complete the remaining work is 10 days

X can do a piece of work in 10 days and Y can do the same work in 15 days if X and Y work for 2 days together after that X left the work then find the time taken by Y to complete the remaining work.1. 10 days2. 12 days3. 8 days4. 15 days

Answer» Correct Answer - Option 1 : 10 days

Given:

Time taken by X to complete the work = 10 days

Time taken by Y to complete the work = 15 days

They both work together for 2 days

Formula used:

Efficiency = Total work/Time taken

Calculation:

LCM of 10 and 15 = 30 = Total work

Efficiency of X = 30/10 units/day

⇒ 3 units/day

Efficiency of Y = 30/15 units/day

⇒ 2 units/day

Total work done by X and Y together in 2 days = (3 + 2) × 2 units

⇒ 10 units

Work remaining = (30 – 10) units

⇒ 20 units

Time taken by Y to complete the work = 20/2 udays

⇒ 10 days

∴ Time taken by Y to complete the remaining work is 10 days

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