InterviewSolution
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InterviewSolution
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x*cos(theta*cot(pi/2 %2B theta)) %2B cosec(pi/2 %2B theta)=sin(pi/2 %2B theta) |
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Answer» cosec(90+$) cos#cot(90+$)=sec$+x cos$-tan$= ==sec$+x(-sin$)=sin(90+$), = sec$+×(sin$)= cos$; =1/cos$+×( sin$)= cos$;=1-xsin$ cos$= cos$^2=1- cos$^2=sin$ cos$=sin$=xsin$ cos$=x=tan$ |
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