x + \(\frac{1}{x}\) = 6 then x2 + \(\frac{1}{x^2}\) = …………�

1.	x + \(\frac{1}{x}\) = 6 then x2 + \(\frac{1}{x^2}\) = ………………A) 19 B) 16 C) 34 D) 10
Answer» Correct option is C) 34 Correct option is (C) 34 x + \(\frac1x\) = 6 \(\Rightarrow\) \((x+\frac1x)^2=6^2\) \(\Rightarrow\) \(x^2+\frac1{x^2}+2=36\) \(\Rightarrow\) \(x^2+\frac1{x^2}\) = 36 - 2 = 34

x + \(\frac{1}{x}\) = 6 then x2 + \(\frac{1}{x^2}\) = ………………A) 19 B) 16 C) 34 D) 10

Answer»

Correct option is C) 34

Correct option is (C) 34

x + \(\frac1x\) = 6

\(\Rightarrow\) \((x+\frac1x)^2=6^2\)

\(\Rightarrow\) \(x^2+\frac1{x^2}+2=36\)

\(\Rightarrow\) \(x^2+\frac1{x^2}\) = 36 - 2 = 34