1.

X g of `CO_(2)` is prepared by the reaction of `CaCO_(3)` and HCl. How many grams of oxygen will be liberated, if X grams of `CO_(2)` completely take part in the process of photosynthesis ? 144 g of water is produced in the first reaction. Equation for photosynthesis is `CO_(2) + H_(2)O to C_(6)H_(12)O_(6)+O_(2)`

Answer» `CaCO_(3) + 2HCl to CaCl_(2) + CO_(2) + H_(2)O`
`6CO_(2) + 6H_(2)O to C_(6)H_(12)O_(6) + 6O_(2)`
Number of moles of water formed in the first reaction = `(144)/18 = 8`
Number of moles of `CO_(2)` produced = 8
Number of moles of oxygen produced by using 8 moles `CO_(2)` is 8 .
Weight of oxygen liberated ` = 32 xx 8 = 256` g


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